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8w^2-26w+15=0
a = 8; b = -26; c = +15;
Δ = b2-4ac
Δ = -262-4·8·15
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-14}{2*8}=\frac{12}{16} =3/4 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+14}{2*8}=\frac{40}{16} =2+1/2 $
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